Question

3log2(x-1)+log2(4)=5

Answer 1

log2(4)=log2(2^2)=2

3log2(x-1)+2=5
3log2(x-1)=3
log2(x-1)=1

generally logx(x)=1 therefore
log2(2)=1
x-1=2
x=3

Answer 2

3log2 (x-1)+log2 4=5

log2[4*(x-1)^3] = 5

4(x-1)^3 = 2^5 = 32



(x-1)^3 = 8

x-1 = 2
x = 3

Answer 3

Have you considered logarithm rules?

\(a\cdot log(b) = log\left(b^{a}\right)\)

\(log(a) + log(b) = log(ab)\)

\(log_{b}(a) = c \iff b^{c} = a\)

Answer 4

GirlByte - how did you get the 32 in your answer?