Question

Solve system by elimination.
Will attach picture, and I will give medals.

Answer 1

Here is the equation

Answer 2

-2x + 2y + 3z = 0
2x + 3y + 3z = 5
----------------add
5y + 6z = 5

2x + 3y + 3z = 5
-2x - y + z = -3
----------------add
2y + 4z = 2

5y + 6z = 5 -->(2)
2y + 4z = 2 -->(-5)
-------------------
10y + 12z = 10 (result of multiplying by 2)
-10y - 20z = -10 (result of multiplying by -5)
--------------add
-8z = 0
z = 0

now sub 0 in for z
5y + 6z = 5
5y + 6(0) = 5
5y = 5
y = 1

now sub 0 in for z and 1 in for y
-2x + 2y + 3z = 0
-2x + 2(1) + 3(0) = 0
-2x + 2 = 0
-2x = -2
x = 1

check...
2x + 3y + 3z = 5
2(1) + 3(1) + 3(0) = 5
2 + 3 = 5
5 = 5 (correct)

x = 1, y = 1, and z = 0

any questions ?

Answer 3

No questions, thanks!

Answer 4

no problem :)