Unsure what I am suppose to do here.

Question

anonymous · Answer

attachment

anonymous · Answer

So I know the function is rewritten as:

$$(x-8)^2-2$$

Which comes out to be the answer I wrote when simplified.

hartnn · Answer

isn't there x+8 ?

anonymous · Answer

Yes I meant x+8, that is the correct answer with x+8 that I have typed in

hartnn · Answer

but but 
you did not solve anything!

hartnn · Answer

you need to solve for x in 
(x+8)^2 -2 =0

anonymous · Answer

how though when there is nothing to solve for? X becomes X^2 and X

anonymous · Answer

Oh ok because it is like the vertex standard equation and by placing that all to 0, you are trying to find the other point at (x,0) that the parabola its.

hartnn · Answer

i just want to solve for x in (x+8)^2 -2 =0 
as the question asked...
start by adding 2 on both sides...

anonymous · Answer

Yes. The answer is:

$$-\sqrt{2}-8, \sqrt{2}-8$$

I just realized how to solve it when you told me to set it to 0 because the standard vertex formula is 

V=(h,k)

$$y = a(x-h)^2+k$$

so we have the vertex with the function I solved and by placing Y = to 0 we are trying to find what the other X value is.

I know the problem simply says to solve for X, but that is the logic behind it that helps me understand why lol. 

Thank for the help.

hartnn · Answer

nice! welcome ^_^