Question

x2+12x-204=0

Answer 1

\[x^2+12x-204=0 \rightarrow ax^2+bx+c=0\]
a= 1, b= 12, c= -204
Let us solve it using quadratic formula.
So,\[ x= \frac{-b \pm \sqrt{b^2-4ac}}{2a}= \frac{-12 \pm \sqrt{12^2-4 \times 1\times (-204)}}{2 \times 1}\]
\[= \frac{-12 \pm \sqrt{144+816}}{2}= \frac{-12 \pm \sqrt{960}}{2}\]
Now solve it further to find your required answer.

Answer 2

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Answer 3

that answer doesn't make any sense to me sorry :L

Answer 4

\[x= \frac{-12 \pm \sqrt{960}}{2}= \frac{-12 \pm \sqrt{64 \times 15}}{2}\]
\[= \frac{-12 \pm \sqrt{8^2 \times 15}}{2}= \frac{-12 \pm 8 \sqrt{15}}{2}\]
\[x= \frac{2(-6 \pm 4 \sqrt{15})}{2}=-6 \pm 4 \sqrt{15}\]
i.e. either \[x = -6+ 4 \sqrt{15}\] or \[x = -6- 4 \sqrt{15}\]
Hence required solution set of the given quadratic equation is:
\[x = [-6- 4 \sqrt{15}, -6+ 4 \sqrt{15}]\]

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