Balance these equations: C5H10+O2....CO2+H2O KCIO3.....KCI+O2 NaOH+CO2...Na2CO3+H2O Cu2O+H2....Cu+H2O Fe+H2O.....Fe3O4+H2 CH3OH+O2......CO2+H2O AgNO3+BaCl 2.....Ba(NO3)2+AgCl H3PO4+NanOH.....Na3PO4+H2O P4+O2..P4O10 Zn+HCI...ZnCl2+H2 SiO2+C.....SiC+CO2 MgO+H2SO4.....MgSO4+H2O As4+O2.....As4O6 Cu+AgNO3.....Cu(NO3)2+Ag C2H5OH+O2....CO2+H2O H2S+O2.....H2O+SO2 Al2O3+HCI..AlCl3+AlCl2+H2O MnO2....Mn3O4+O2 Al+Fe2O3....Al2O3+Fe Na+H2O...NaOH+H2
I already got the answers for the first 9, but i have no idea if they are correct or not.
post your work and then someone might comment
ok, one moment, here is the first 9
Zn + 2HCl..ZnCl2+H2 SiO2+C....SiC+CO2 (balanced) MgO+H2SO4...MgSO4+H2O (balanced) As4+O2......As4O6 (balanced? because 4+2=6) 2Cu+AgNO3......Cu(NO3)2+Ag
As4+O2......As4O6 (balanced? because 4+2=6)????? As bal your O's are not
C2 H5 O2 H+O2.....CO2+H2O ? H2S+O2.......H2O+SO2 (balanced) Al2 O3+H2 CI......AlCl3+H2O
As4+O2........As4 2O6 ?????
no try again
hint change left side
2Cu+AgNO3......Cu(NO3)2+Ag this needs work (NO3)2 one on left side 2 on right??
As4+O2........As4 2O6 ? but how can i change the 6? it makes no sense, since there are only 2 O molecules?
As4+3O2........As4 2O6 3*O2 = 6 O's
so: As4+3O2......As4O6
you have to multiply the subscript by coefficient
ok, so O is now correct, since 2*3=6, and the right side of the equation has 6 O molecules
yes
ok, thanks!
2Cu+AgNO3......Cu(NO3)2+Ag this needs work (NO3)2 one on left side 2 on right?? do this because i have to go
ok
Cu+AgNO3......Cu(NO3)2+Ag Is it already balanced???
no you have (NO3)2 on the right and only 1 on the left
so: Cu+2AgNO3....Cu(NO3)2+Ag
now you have 2 Ag's on right and one on left
Cu+Ag 2NO3........Cu(NO3)2+Ag or would I need "( )"???
Cu+2AgNO3......Cu(NO3)2+2Ag that is balance 1Cu L--1Cu rt 2Ag L--2Ag rt 2NO3 L --2NO3 Rt gotta run good luck!! just count
Omg! That's...a lot of questions. lOL
which ones do you still need help with?
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