Question

From a stack of 3 dice, one is taken and rolled twice.
If, unknown to the gambler, one of the dice is weighted and has a 1/8 chance of rolling a 6, what is the probability that the gambler rolls two 6's?

Answer 1

ok... i am not sure of this,
you have three die.... only one is weighted....

so there are two dice that are "clean"...

we KNOW that the probability of throwing a "clean" two sixes is (1/6)(1/6) since there is a 1/6 chance of throwing a 6 each time you throw... so there are 2 chances of getting this...
IF you chose the weighted die... there would be a (1/8)(1/8) chance of throwing a six with this die each time you throw (given)

so i would say the probability of rolling two sixes with these die would be these probabilities added together...

(1/6)(1/6)+(1/6)(1/6)+(1/8)(1/8)=
(1/36)+(1/36)+(1/64)

but that's just what i think ....