Question

simplify cotx sinx-sin(pi/2-x)+cotx
plz help i'm so lost

Answer 1

sin(pi/2-x)=cos x

Answer 2

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Answer 3

@surjithayer okay is that the formula i need to use?

Answer 4

\(\bf cot(x)sin(x)-sin\left(\frac{\pi}{2}-x\right)+cot(x)\\ \quad \\\implies cot(x)sin(x)-cos(x)+cot(x)\\ \quad \\
\cfrac{cos(x)}{sin(x)}sin(x)-cos(x)+\cfrac{cos(x)}{sin(x)}\)

Answer 5

recall that \(\bf cot(\theta) = \cfrac{cos(\theta)}{sin(\theta)}\)

Answer 6

@jdoe0001 yes i do now how exactly do i plug the question in?

Answer 7

well, you just want to simplify I gather, so cancel any like-terms and add, see what you're left with

Answer 8

\(\bf \cfrac{cos(x)}{\cancel{sin(x)}}\cancel{sin(x)}-cos(x)+\cfrac{cos(x)}{sin(x)}\)

Answer 9

@jdoe0001 yup so would my answer be cosx or 2 cosx

Answer 10

\(\bf \cfrac{cos(x)}{\cancel{sin(x)}}\cancel{sin(x)}-cos(x)+\cfrac{cos(x)}{sin(x)}\implies cos(x)-cos(x)+\cfrac{cos(x)}{sin(x)}\)

see anyting you can cancel out?

Answer 11

@jdoe0001 yes -cos(x) and cos(x)

Answer 12

yeap, and you're left with that, with will be just cot(x) :)

Answer 13

omg thank you so much! @jdoe0001

Answer 14

yw