Solve triangle ABC given that A = 56 degrees, B = 57 degrees, and b = 9.
Use the fact that the interior angles of a triangle add to 180 degrees to find Angle C. Use law of sines to find the the lengths of sides a and c: \[\frac{\sin A}{a} = \frac{\sin B}{b} = \frac{\sin C}{c}\]
So: sin 56/a = sin 57/9 = sin 67/c right?
Yes, that appears to be correct. Now to solve for a and c, simply pair the following equations together: \[\frac{\sin 56}{a} = \frac{\sin 57}{9}\] \[\frac{\sin 57}{9} = \frac{\sin 67}{c}\]
Make sure you are in degree mode if you use a calculator to solve.
What do you mean degree mode?
on your calculator there is a button that says Radians and if you click on it will say degree's where it said Radians
I'm not finding a Radians button :/
What kind of calculator do you have?
TI 83 Plus
Do you see a mode button?
yes!
Go to it and tell me what you see after clicking it.
I see the radian / degree option and it's already on degree
thanks so much for the help!
You're welcome
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