What formula would I use to solve this? During a softball game, a batter hits a ball upward from an initial height of 3 feet. The height, in feet, of the softball is given by s(t)= -16t^2+70t+3, where t is the time in seconds and t>=0 Which is the closest to the time when the softball will be 50 feet above the ground?
hmm, normally i would say put s(50) and solve the equation to find t, but the way they state the question it makes me wonder if you can even solve for s(50).
Man i'm too tired for this stuff, i obviously meant s = 50 not s(50)
\[50=-16t^2+70t+3\] if that possible to solve?
oh right i misinterpret the question too, lol well, than that's your answer right there.
What you basically do, is you take the "graph" H(x)=50 which is just a horizontal line of 50 s above the x-axis. and than try to find where the graph of your given equation would cross that line. It's the same as solving for f(x)=0 except 50 places higher, does that make sense?
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