simplify the expression below
\[\frac{ -5+i }{ 2i }\]
Multiply the top and bottom by i
\[\frac{ -10i+2i }{ 4i }\] i tried, but i have no idea if thats right though..
oh wait i wasnt supposed to multiply by 2i???
You can but the 2 will can be factored out and canceled. So multiply by i is better. Also i times i = i squared = -1
@agent0smith
im still confused!
\[\frac{ -5 + i }{ 2i } \times \frac{ i }{ i } = \frac{ -5i + i ^{2} }{ 2i ^{2} }\]
\[i = \sqrt{-1}\]\[i ^{2} = -1\]
i^2 = -1. then as ranga put just simplify the values from there -5i + (-1) / 2(-1)
ok i understand that part, im just exactly sure how to simplify it now.
\[\frac{ -5i + i ^{2} }{ 2i ^{2} } = \frac{ -5i - 1 }{ -2 } = \frac{ 1 + 5i }{ 2 }\]
how did they become positive?
Factor out -1 from top and bottom and they will cancel out.
For example: -5 / -3 = 5 / 3
how did you get the three?
I was just giving an example of dividing two negative numbers and how the negatives will cancel out.
\[\frac{ -5i - 1 }{ -2 } = \frac{ (-1)(5i + 1) }{ -1(2)} = \frac{ 1+ 5i }{ 2 }\]
now what do i do?
That is it. You have simplified the expression. You have gotten rid of the i in the denominator.
there is nothing more that you can do to simplify it?
If you want you can write it as:\[\frac{ 1 + 5i }{ 2 } = \frac{ 1 }{ 2 } + \frac{ 5i }{ 2 }\]
but either one is considered correct?
Is the answer different from any of the above?
no? haha
ok i got it, thank you!
you are welcome.
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