2x^2 -1 can also be written as...?
I did this ... and I was able to get 2(x+1)(x-1) Not sure if I'm correct.
You basically have to just factor that buddy up there..
Thats the only way I see it being written.
Wait. I think Im wrong. Double checking.
^^^ you can factor 2 out if it was 2x^2 - 2 but not when it is 2x^2 - 1
thank you!
Yeahh! I just realized that -1 !!! haha.
So therefore, you would have to find two numbers that will give you -1 but added give you 0. Then factor. Right? @ranga
Using the identity: \[\Large a ^{2} - b^{2} = (a + b)(a - b)\] we can write \[\Large 2x ^{2} - 1 = (\sqrt{2}x + 1)(\sqrt{2}x - 1)\] But that introduces radicals even though it does factorize it.
Okay! That was way out of my league! Thought I was on the right track.... when .... I clearly wasn't. Hahaa! We learn something new everyday don't we. Lol.
Ranga, when your completed with this, would you be up to help me with a question of mine that I wish you could help me get the answer to? @ranga
rbeckford134: sure post it on a separate thread and message me the link.
Sounds good bud! Ill post it now. Thanks!
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