Let R={(1,5),(2,2),(3,4)(5,2)} S={(2,4),(3,4),(3,1),(5,5)} Find:
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OpenStudy (anonymous):
R dot S
OpenStudy (anonymous):
\[R\circ S\] right?
OpenStudy (anonymous):
Yes
OpenStudy (anonymous):
first we do \(S\), then we do \(R\)
lets go slow
OpenStudy (anonymous):
what is \(S(2)\)?
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OpenStudy (anonymous):
for that you need to look here
\[S=\{(2,4),(3,4),(3,1),(5,5)\}\]
OpenStudy (anonymous):
ok so that is 2,4
OpenStudy (anonymous):
you see the "ordered pair" \((2,4)\) so \(S(2)=4\) i.e. \(S\) sends \(2\) to \(4\)
OpenStudy (anonymous):
okay
OpenStudy (anonymous):
then what does \(R\) do to \(4\)?
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OpenStudy (anonymous):
R sends it to 3?
OpenStudy (anonymous):
no not quite
do you see any ordered pair in \(R\) where the first number is \(4\) ?
OpenStudy (anonymous):
no
OpenStudy (anonymous):
neither do i
so \(R\) does not have \(4\) in its domain, so
\[R\circ S\] does not have \(2\) in its domain
skip that one, lets move on
OpenStudy (anonymous):
ok so if it is s(3) then that sends it to 4 which i also see none in R
but if i see s(3) then it sends to 1 so then in R 1 is sending it to 5 then my answer would be (1,5)
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OpenStudy (anonymous):
yes exactly
OpenStudy (anonymous):
oh no hold on!
OpenStudy (anonymous):
ok so then the last one would be s(5) sends to 5 then on R 5 sends to 2 so then my answer is (5,2)?
OpenStudy (anonymous):
you wrote \but if i see s(3) then it sends to 1 so then in R 1 is sending it to 5 then my answer would be (1,5)
which is almost right except for the last line
OpenStudy (anonymous):
so then i switch?
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OpenStudy (anonymous):
S sends 3 to 1
R sends 1 to 5
so \(R\circ S\) sends 3 to 5
ordered pair is \((3,5)\)
OpenStudy (anonymous):
okay
OpenStudy (anonymous):
i think i go it
OpenStudy (anonymous):
got*
OpenStudy (anonymous):
also \(S\) sends 5 to 5, and \(R\) sends 5 to 2 so \(R\circ S\) sends 5 to 2
ordered pair is \((5,2)\)
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OpenStudy (anonymous):
and those are the only ordered pairs for \(R\circ S\)
you got it? do you have another one to do?
OpenStudy (anonymous):
and if it was S dot Rwould i start with R?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
Yes i have another let me work it out and ill give you my answers
OpenStudy (anonymous):
ok i will do S dot R
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OpenStudy (anonymous):
kk
OpenStudy (anonymous):
ok and while you do it i will copy it down here so i don't have to keep scrolling up
Let \(R=\{(1,5),(2,2),(3,4)(5,2)\} ,S=\{(2,4),(3,4),(3,1),(5,5)\} \)
OpenStudy (anonymous):
ok I got (2,4), (4,1) (4,4), (2,5)
OpenStudy (anonymous):
is that for \(S\circ R\)?
OpenStudy (anonymous):
yes
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OpenStudy (anonymous):
ok then we better go slow
OpenStudy (anonymous):
okay
OpenStudy (anonymous):
the first ordered pair i see in \(R\) is \((1,5)\) meaning \(R\) send \(1\) to \(5\)
so we start with \((1,?)\)
OpenStudy (anonymous):
then ask what does \(S\) do with \(5\)?
OpenStudy (anonymous):
sends to 5
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OpenStudy (anonymous):
k good
so the first ordered pair of \(S\circ R\) is \((1,5)\)
OpenStudy (anonymous):
okay
OpenStudy (anonymous):
the next ordered pair i see in \(R\) is \((2,2)\) meaning \(R\) sends 2 to 2
now we write \((2,?)\)
what does \(S\) do with \(2\) ?
OpenStudy (anonymous):
sends to 4
OpenStudy (anonymous):
ok so what is the ordered pair for \(S\circ R\) that starts \((2,?)\) ?
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OpenStudy (anonymous):
2,4
OpenStudy (anonymous):
got it
now on to the next one
OpenStudy (anonymous):
the next one is none
OpenStudy (anonymous):
i see \((3,4)\) meaning... right none
so we don't include a pair starting at 3
OpenStudy (anonymous):
(5,4) for the last?
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OpenStudy (anonymous):
yes
OpenStudy (anonymous):
you see you are just chasing through the ordered pairs
important to know which one comes first is all
OpenStudy (anonymous):
Ok it makes much mored send i just have to take it slow thank you you for explaining
OpenStudy (anonymous):
yw, hope it is more or less clear
OpenStudy (anonymous):
sense*
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OpenStudy (anonymous):
thank you
OpenStudy (anonymous):
i like "mored send" too
OpenStudy (anonymous):
lol thanks im gonna get back to doing the other problems