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Mathematics 17 Online
OpenStudy (anonymous):

Let R={(1,5),(2,2),(3,4)(5,2)} S={(2,4),(3,4),(3,1),(5,5)} Find:

OpenStudy (anonymous):

R dot S

OpenStudy (anonymous):

\[R\circ S\] right?

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

first we do \(S\), then we do \(R\) lets go slow

OpenStudy (anonymous):

what is \(S(2)\)?

OpenStudy (anonymous):

for that you need to look here \[S=\{(2,4),(3,4),(3,1),(5,5)\}\]

OpenStudy (anonymous):

ok so that is 2,4

OpenStudy (anonymous):

you see the "ordered pair" \((2,4)\) so \(S(2)=4\) i.e. \(S\) sends \(2\) to \(4\)

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

then what does \(R\) do to \(4\)?

OpenStudy (anonymous):

R sends it to 3?

OpenStudy (anonymous):

no not quite do you see any ordered pair in \(R\) where the first number is \(4\) ?

OpenStudy (anonymous):

no

OpenStudy (anonymous):

neither do i so \(R\) does not have \(4\) in its domain, so \[R\circ S\] does not have \(2\) in its domain skip that one, lets move on

OpenStudy (anonymous):

ok so if it is s(3) then that sends it to 4 which i also see none in R but if i see s(3) then it sends to 1 so then in R 1 is sending it to 5 then my answer would be (1,5)

OpenStudy (anonymous):

yes exactly

OpenStudy (anonymous):

oh no hold on!

OpenStudy (anonymous):

ok so then the last one would be s(5) sends to 5 then on R 5 sends to 2 so then my answer is (5,2)?

OpenStudy (anonymous):

you wrote \but if i see s(3) then it sends to 1 so then in R 1 is sending it to 5 then my answer would be (1,5) which is almost right except for the last line

OpenStudy (anonymous):

so then i switch?

OpenStudy (anonymous):

S sends 3 to 1 R sends 1 to 5 so \(R\circ S\) sends 3 to 5 ordered pair is \((3,5)\)

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

i think i go it

OpenStudy (anonymous):

got*

OpenStudy (anonymous):

also \(S\) sends 5 to 5, and \(R\) sends 5 to 2 so \(R\circ S\) sends 5 to 2 ordered pair is \((5,2)\)

OpenStudy (anonymous):

and those are the only ordered pairs for \(R\circ S\) you got it? do you have another one to do?

OpenStudy (anonymous):

and if it was S dot Rwould i start with R?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

Yes i have another let me work it out and ill give you my answers

OpenStudy (anonymous):

ok i will do S dot R

OpenStudy (anonymous):

kk

OpenStudy (anonymous):

ok and while you do it i will copy it down here so i don't have to keep scrolling up Let \(R=\{(1,5),(2,2),(3,4)(5,2)\} ,S=\{(2,4),(3,4),(3,1),(5,5)\} \)

OpenStudy (anonymous):

ok I got (2,4), (4,1) (4,4), (2,5)

OpenStudy (anonymous):

is that for \(S\circ R\)?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

ok then we better go slow

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

the first ordered pair i see in \(R\) is \((1,5)\) meaning \(R\) send \(1\) to \(5\) so we start with \((1,?)\)

OpenStudy (anonymous):

then ask what does \(S\) do with \(5\)?

OpenStudy (anonymous):

sends to 5

OpenStudy (anonymous):

k good so the first ordered pair of \(S\circ R\) is \((1,5)\)

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

the next ordered pair i see in \(R\) is \((2,2)\) meaning \(R\) sends 2 to 2 now we write \((2,?)\) what does \(S\) do with \(2\) ?

OpenStudy (anonymous):

sends to 4

OpenStudy (anonymous):

ok so what is the ordered pair for \(S\circ R\) that starts \((2,?)\) ?

OpenStudy (anonymous):

2,4

OpenStudy (anonymous):

got it now on to the next one

OpenStudy (anonymous):

the next one is none

OpenStudy (anonymous):

i see \((3,4)\) meaning... right none so we don't include a pair starting at 3

OpenStudy (anonymous):

(5,4) for the last?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

you see you are just chasing through the ordered pairs important to know which one comes first is all

OpenStudy (anonymous):

Ok it makes much mored send i just have to take it slow thank you you for explaining

OpenStudy (anonymous):

yw, hope it is more or less clear

OpenStudy (anonymous):

sense*

OpenStudy (anonymous):

thank you

OpenStudy (anonymous):

i like "mored send" too

OpenStudy (anonymous):

lol thanks im gonna get back to doing the other problems

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