An inverted pyramid is being filled with water at a constant rate of 65 cubic centimeters per second. The pyramid, at the top, has the shape of a square with sides of length 3 cm, and the height is 5 cm.

Find the rate at which the water level is rising when the water level is 2 cm.

Question

An inverted pyramid is being filled with water at a constant rate of 65 cubic centimeters per second. The pyramid, at the top, has the shape of a square with sides of length 3 cm, and the height is 5 cm.

Find the rate at which the water level is rising when the water level is 2 cm.

anonymous · Answer

dA/dt = 1/3(2B (dB/dt x dH/dt)? o.o

anonymous · Answer

dy/dt = ((1/3)(65) - 2xy)/x^2 o-o If i'm reading that right

anonymous · Answer

@Psymon  Check my work ... yea you read it right.

psymon · Answer

What did you have in mind from there, mebs? Its not what I was thinking actually.

anonymous · Answer

Well, what were you thinking. I would like to know.

anonymous · Answer

Give a brief outline of the plan.

anonymous · Answer

I feel like I made a error somewhere. This is that feeling I get when I do Related Rates problems...

psymon · Answer

Well, since the width and height of the water are never constant, I think you have to solve for one in terms of the other. Since you want dh/dt, I think you need to eliminate the base variable:

|dw:1383111470022:dw|

|dw:1383111549104:dw|