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Mathematics 19 Online
OpenStudy (anonymous):

compound intrest formula! help

OpenStudy (kira_yamato):

Do you know the formula for the sum to the nth term of a geometric progression?

OpenStudy (anonymous):

well i know the formula, i just need some help putting my question into it

OpenStudy (kira_yamato):

Suppose you have n periods of interest, and r being the rate of interest (i.e. your common ratio is (1+r)). Principle amount is P, (i.e. T(1) = P), and \[n \in \mathbb{Z}^+\]

OpenStudy (anonymous):

ok well i have $10000 loan, for 5 years with 6% inrtrest

OpenStudy (anonymous):

but im not sure how to put into the formula

OpenStudy (kira_yamato):

In this case, P = 10000, n = 5 and r = 0.06 i.e. common ratio = 1.06 Plug that into the formula for the sum of a geometric progression.

OpenStudy (kira_yamato):

This gives you the total amount you owe after 5 years

OpenStudy (anonymous):

so do i use this?

OpenStudy (anonymous):

\[p = (1 + \frac{ r }{ n }) nt\]

OpenStudy (kira_yamato):

No. \[A = P \times \frac{r^n - 1}{r-1}\]

OpenStudy (kira_yamato):

In this case, plug in r = 1.06, P = 10000, n = 5

OpenStudy (wolf1728):

total = principal * (1 + rate) ^ years but that is for investing Here is a loan payment formula That's from my website http://1728.org/loanform.htm

OpenStudy (kira_yamato):

Why the the Sn formula flipped?

OpenStudy (kira_yamato):

Or it's not even the Sn formula...

OpenStudy (anonymous):

wait which formula do i use to find how much i would owe after 5 years at 6% intrest and starting amt of $10000

OpenStudy (anonymous):

\[10000 x \frac{ 5^{0.06 - 1} }{ 5 - 1}\]

OpenStudy (kira_yamato):

\[10000 \times \frac{1.06^5 - 1}{0.06}\]

OpenStudy (kira_yamato):

Note that r = 1.06 while n = 5. You went the other way around.

OpenStudy (wolf1728):

muppz - you stated the loan is for 5 years. Yet you also stated which formula do i use to find how much i would owe after 5 years at 6% intrest and starting amt of $10000 So the loan is for more than 5 years?

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