Question

Hi all! I have a question "Take the derivative of a^3 +cosx^3"

Answer 1

I think you use the chain rule

Answer 2

So I came up with 3(a)^2 (1)+3(cosx)(-sinx)

Answer 3

I am a little rusty but I think it might be 3a^2 + -3x^2 sin x^3

Answer 4

Hmm did you use the chain rule?

Answer 5

is it 3x^2 or 3a^2? because it would be a whole different equation then

Answer 6

a to the power of 3 plus cos power 3 x

Answer 7

uhm in that case I think a^3 is just 3a^2 then

Answer 8

and cosx?

Answer 9

actually a^3 = 0

Answer 10

the derivative of a^3 is = 0 because a is a constant

Answer 11

therefore you just need to use the chain rule on costx^3

Answer 12

cosx^3*

Answer 13

it will end being -sin(x)3cos^2(x)

Answer 14

hmm so a is constant, which is why the derivative/slope is 0?

Answer 15

ok just checked back over my answer that' what I got now

Answer 16

3(a)^2(0)+3(cosx)^2 (-sinx)

Answer 17

yes

Answer 18

cool, thanks :)

Answer 19

no problem