the slope of tangent at point (h,h) of circle x2 + y2=a2 is
to find slope of tangent at point x=h, you will need f'(h) so could you first differentiate \(x^2+y^2 =a^2 \)?
i already do this but answer is wrong
what did you get ? y' =... ?
i taken x and y both as h
yes, thats correct, but you will plug in x=h, y=h in y' only, right ?
there's an easy way and a hard way for this problem. are you doing it by analysis or by differentiation?
did you implicitly differentiate x^2+y^2=a^2 ?
no i'm simply solving it by analysing
|dw:1383040431172:dw|
|dw:1383040470642:dw| look at these two points
not understand can anyone pls
This is the circle x2 + y2=a2 graphed on the coordinate plane |dw:1383041014270:dw| this is all points that can be expressed as (h,h) x=y |dw:1383041082650:dw|
putting the two graphs together, we have |dw:1383041127577:dw| those two points (ignore the square)
draw the tangents at those two points.
yes i got it
sorry for the confusion
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