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Mathematics 13 Online
OpenStudy (anonymous):

the slope of tangent at point (h,h) of circle x2 + y2=a2 is

hartnn (hartnn):

to find slope of tangent at point x=h, you will need f'(h) so could you first differentiate \(x^2+y^2 =a^2 \)?

OpenStudy (anonymous):

i already do this but answer is wrong

hartnn (hartnn):

what did you get ? y' =... ?

OpenStudy (anonymous):

i taken x and y both as h

hartnn (hartnn):

yes, thats correct, but you will plug in x=h, y=h in y' only, right ?

OpenStudy (anonymous):

there's an easy way and a hard way for this problem. are you doing it by analysis or by differentiation?

hartnn (hartnn):

did you implicitly differentiate x^2+y^2=a^2 ?

OpenStudy (anonymous):

no i'm simply solving it by analysing

OpenStudy (anonymous):

|dw:1383040431172:dw|

OpenStudy (anonymous):

|dw:1383040470642:dw| look at these two points

OpenStudy (anonymous):

not understand can anyone pls

OpenStudy (anonymous):

This is the circle x2 + y2=a2 graphed on the coordinate plane |dw:1383041014270:dw| this is all points that can be expressed as (h,h) x=y |dw:1383041082650:dw|

OpenStudy (anonymous):

putting the two graphs together, we have |dw:1383041127577:dw| those two points (ignore the square)

OpenStudy (anonymous):

draw the tangents at those two points.

OpenStudy (anonymous):

yes i got it

OpenStudy (anonymous):

sorry for the confusion

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