how to solve (8)3^x = 5 ?
\[(8)3^{x} = 5\] , find x.
@hartnn
sure its , \(8\times 3^x = 5\) ? take log on both sides, what do u get ?
@hartnn Would it be more intuitive if we divide throughout by 8 first?
yes, dividing by 8 is better step
my answer is x = 1.62 , im not sure whether correct or not. @hartnn
i don't think thats correct...how you got that value ?
and you will get value in terms of log.... unless i misintrepret the question...
\[\log 8 \ * log 3^{x} = \log 5\] log 8 * x log 3 = log 5 x log 3 = log 5/log 8 x = log 5 / log 8 / log 3 x = 1.62 these are my steps
@jayjayokocha divide by 8 on both side. take log base 10. put value of log5,log5/8(=log5-log8). do it, get ASNWER.
you are not appling log rules correctly.
lets first divide by 8 on both sides, 3^x = 5/8 now take log on both sides
use, \(\Large \log a^b=b \log a\)
so, now i got xlog3 = log 5 - log 8 , what's next ?
just divide both sides by log 3 and you would have got 'x' thats it!
answer is -0.428 ?
YES. thats the approximate answer :)
just a quick one , 2^x = 5 answer is x = 2.32 ? @hartnn
yes, thats also correct :)
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