OpenStudy (anonymous):

can someone explain this to me?

5 years ago
OpenStudy (anonymous):

(integral of tan^5x.sec^7x), could you explain it to me step by step? from the splitting step

5 years ago
OpenStudy (loser66):

tan ^5 sec^7 = tan^4 sec^6 tan sec , right?

5 years ago
OpenStudy (anonymous):

yes, then do you do (tan^2)^2sec^6tan sec?

5 years ago
OpenStudy (loser66):

yup

5 years ago
OpenStudy (loser66):

tan^2 = sec^2 -1, now I use t to indicate tan and s to indicate sec, ok?

5 years ago
OpenStudy (anonymous):

is that as in substitution or for shorthand purposes?

5 years ago
OpenStudy (loser66):

(s -1)^2 *s^6 ts dx let u = s --> du = ts dx

5 years ago
OpenStudy (anonymous):

ok i got that part

5 years ago
OpenStudy (loser66):

yours = (u-1)^2 u^6 du = (u^2 -2u +1) u^6 du = u^8 - 2u^7 +u^6 quite easy now

5 years ago
OpenStudy (anonymous):

yes it is, thanks a bunch!

5 years ago
OpenStudy (loser66):

np

5 years ago