Find the Derivative 3x^4 + cot2x
Remember the power rule and the chain rule. And also the fact that you can break up a derivative that is the sum of things... which has a name that I don't remember. :D (Sum rule, maybe?)
Can you help me solve for it?
I did help you. What part are you having trouble with?
Not exactly, I'm not sure how to break it down?
You can find the derivative of \(3x^4\) and \(\cot 2x\) separately and then add them together. So we'll start with \(3x^4\). Do you remember the power rule?
yea, it will be 12x^3.
Ok, so it will be \(12x^3 + \frac{d}{dx}(\cot 2x)\). Do you know the derivative of the cotangent?
yea its -csc^2x
Yes. So now just apply the chain rule and you have the answer.
so will the answer be \[f'(x)= 12x^3 \cot2x+ 3x^4(-\csc^2x)\]
Join our real-time social learning platform and learn together with your friends!