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a car is initially traveling at a speed of 10 m/s. it then accelerates 20 m/s2 for 3 seconds. what is the speed of the car after 3 seconds
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\[a=\frac{ v-v_0 }{t}\]\[v=v_0+at\]
Well you could use the formula:\[v _{f}=v _{i}+at\] Where vf is the final velocity, vi the initial velocity,a the acceleration,and t the time. So plug in the values they gave you 10 m/s for vi, 20 m/s^2 for a,and 3 seconds for t:\[v _{f}=10 m/s+(20 m/s^2)(3 s)\] First multiply out the "at term":\[v _{f}=10 m/s+60 m/s\] See how i multiplied the 20 m/s^2 and 3m/s to get an answer in m/s (60m/s) Simplify:\[v _{f}=70 m/s\] We get 70 m/s. ANSWER:70 METERS PER SECOND
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