Question

Solve 8t + 16 > 16t - (12t - 20). please explain

A. {t| t > 1}
B. {t| t > -1}
C. {t| t < 4}
D. {t| t > 4}

Answer 1

@jessica1313, what can we do first to solve this?

Answer 2

add all the t's?

Answer 3

We will eventually get it to that. I would say the first step would be to figure out a way to get rid of those parentheses.

Answer 4

There are two thiings we could do to get rid of them.

Answer 5

pemdas

Answer 6

multiply :B

Answer 7

Exactly :)

But in this case, we can't really do anything inside the parentheses.

Answer 8

That was meant for @jessica1313.

Answer 9

do you multiply the 16 with the parentheses?

Answer 10

We cannot multiply anything just yet. If you let me, I will explain wht to do.

Answer 11

pfft alright then

Answer 12

What we need to do first is we can either distribute the negative in front of
(12t - 20) using the distributive property Recall that a(b + c) = ab + ac

Answer 13

We can use the distributive property OR we can simply add (12t - 20) to both sides.

Answer 14

Now if we add (12t + 20) to both sides we end up with

(12t - 20) + 8t + 16 > 16t

Answer 15

In this way, since there is nothing in front of (12t - 20) we can simply get rid of the parentheses.

Answer 16

When we do that we get:

12t - 20 + 8t + 16 > 16t

Answer 17

The next thing to do is remember that we are solving for t.

Answer 18

In other words, we should put all the terms with variable t on one side, then put all the integers on the other side.

Answer 19

Using algebra of course....

When we do that we end up with;

Answer 20

12t + 8t - 16t > 20 - 16

@chickensx, do you see how I get this?

Answer 21

Have you solved for t yet?

Answer 22

Great job

Answer 23

Make sure you check your work.

Answer 24

mkay (: