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OpenStudy (anonymous):
Eliminate the parameter. x = t2 + 1, y = t2 - 1
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OpenStudy (amoodarya):
x-y=2
OpenStudy (anonymous):
\[ x = t^2 + 1 \quad \quad\quad y = t^2 - 1 \\ t^2 = x - 1 \\ y = t^2 - 1 \quad \to \quad y = (x - 1) - 1 \\ y = x - 2 \]
OpenStudy (anonymous):
y = x + 2, x ≥ 1 y = x - 2, x ≥ 1 y = x2 - 2, x ≥ 1 y = x2 + 2, x ≥ 1
OpenStudy (anonymous):
so its b
OpenStudy (anonymous):
yes
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OpenStudy (amoodarya):
x=t^2+1>=1
OpenStudy (anonymous):
Eliminate the parameter. x = square root of t, y = 4t + 1
OpenStudy (anonymous):
y = 4square root of x - 1, x ≥ 0 ?
OpenStudy (amoodarya):
x^2=t so put t in y=4t+1
OpenStudy (anonymous):
y = 4square root of x + 1, x ≥ 0 y = 4square root of x - 1, x ≥ 0 y = 4x2 - 1 y = 4x2 + 1
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OpenStudy (amoodarya):
y=4(x^2)-1
OpenStudy (anonymous):
Eliminate the parameter. x = 3t, y = t + 7
OpenStudy (amoodarya):
t=y-7 put it in x=3t y=3(y-7) then simplify
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