Question

Eliminate the parameter.

x = t2 + 1, y = t2 - 1

Answer 1

x-y=2

Answer 2

\[
x = t^2 + 1 \quad \quad\quad y = t^2 - 1 \\
t^2 = x - 1 \\
y = t^2 - 1 \quad \to \quad y = (x - 1) - 1 \\
y = x - 2
\]

Answer 3

y = x + 2, x ≥ 1

y = x - 2, x ≥ 1

y = x2 - 2, x ≥ 1

y = x2 + 2, x ≥ 1

Answer 4

so its b

Answer 5

yes

Answer 6

x=t^2+1>=1

Answer 7

Eliminate the parameter.

x = square root of t, y = 4t + 1

Answer 8

y = 4square root of x - 1, x ≥ 0 ?

Answer 9

x^2=t
so put t in y=4t+1

Answer 10

y = 4square root of x + 1, x ≥ 0

y = 4square root of x - 1, x ≥ 0

y = 4x2 - 1

y = 4x2 + 1

Answer 11

y=4(x^2)-1

Answer 12

Eliminate the parameter.

x = 3t, y = t + 7

Answer 13

t=y-7
put it in x=3t
y=3(y-7)
then simplify