Question

f(x)=x^2+6x-7

Answer 1

Remember:
\[ax^2+bx+c=0\]
If what you are asking is how to solve:
\[x^2+6x-7=0\]
then you can complete the square:
Start by adding 7 to both sides so you get:
\[x^2+6x=7\]

Divide "b-term" by 2 and then square it and add it to both sides so:
\[x^2+6x+9=16\]
(basically i am doing half of 6 and squaring it and adding it to both sides.

then factor the left side by doing (x+b-term/2)(x+b-term/2):
(x+3)(x+3)=16

becomes:
\[(x+3)^2=16\]


take the square root of both sides:
x+3= -4 or x+3 = 4

subtract 3 from both sides:
x=1
or
x=−7