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Calculus1
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log3(log3 x) = 1
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\[\log_{3} (\log_{3}x)=1 \]
\[3^{3^{3}}\]
what?
to reverse the LOG function, you take the exponent. \[x^{a}\] since the log is applied twice, you need to exponentiate twice, giving 3 to the power of 3 to the power of 3 \[3^{3^{3}}\]
taken from Wikipedia: In mathematics, an inverse function is a function that undoes another function: If the function f applied to an input x gives a result of y, then applying the inverse function g to y gives the result x, and vice versa.
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i dont understand lol \[(3^3)^3 \] does not = 1
thanks man just figure it out lol... when the log is on the right side of the equation my mind flutters me
no problem. glad I could help.
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