Question

Find h'(1) given h(x) = f(x^(1/2))
f(1) = 9
f'(1) = 3

Answer 1

well using chain rule
h'(x) = d(x^(1/2))/dx * f'(x^(1/2))
h'(x) = (1/2)*x^(-1/2)*f'(x^(1/2))
sub in x = 1
h'(1) = (1/2)*1*f'(1)
f'(1) = 3 so
h'(1) = 3/2

Answer 2

hope that helps, i'm not sure it's right because
I didn't use f(1) = 9

Answer 3

Nope, that was right. Thanks a lot! (the f(1) = 9 was for a different part of the problem, I figured I'd include it just in case I had been approaching the whole thing all wrong).

Answer 4

lol