Prove the identity (csc x - cot x)(sec x + 1) = tan x And please show me how you did it
\[\csc(x) = \frac{ 1 }{ sin(x) }\] \[\cot(x) = \frac{ 1 }{ \tan(x) }=\frac{ \cos(x) }{ sin(x) }\] \[\cos^2(x)=1-\sin^2(x)\]
\[(\csc(x)-\cot(x))=\left( \frac{ 1 }{ \sin(x)}-\frac{ \cos(x) }{ \sin(x) } \right) = \left( \frac{ 1-\cos(x) }{ \sin(x) } \right)\] \[(\sec(x)+1)=\left( \frac{ 1 }{ \cos(x) } +\frac{ \cos(x) }{ \cos(x) }\right)=\left( \frac{ 1+\cos(x) }{ \cos(x) } \right)\]
\[\left( \frac{ 1-\cos(x) }{ \sin(x) } \right)\left( \frac{ 1+\cos(x) }{ \cos(x) } \right)=\frac{ 1-\cos^2(x) }{ \sin(x)\cos(x) }=\frac{ 1-(1-\sin^2(x) }{ \sin(x)\cos(x) }\]
\[=\frac{ \sin^2(x) }{ \sin(x)\cos(x) }=\frac{ \sin(x) }{ \cos(x) }=\tan(x)\]
Wow...thank you sooo much Lessis! I really understand all that now..You're great :)
I have one more, do you think you can help me with that as well? If you don't mind.
Sure.
And thank you for going step by step
Prove that this is not an identity sin x + cos x = 1
Do you know how to prove something by contradiction?
No, I don't. This whole proof thing is all very confusing for me.
A proof by contradiction, is when you demonstrate that something is true by assuming it's false and getting a contradiction. As an example, I'll demonstrate that all blue shirt wearing guys, have a blue shirt. Assuming that statement is false, then some blue shirt wearing guys don't have a blue shirt. But if they don't have a blue shirt, then they can't be wearing a blue shirt, which is a contradiction. Then every blue shirt wearing guy MUST have a blue shirt.
Hmm..I see what you're saying.
To prove that sin(x) + cos(x) = 1 isn't an identity, suppose that it actually IS an identity. If that equation is an identity, then for every "x" value you give, sin(x)+cos(x)=1. But for x=pi/4 or 45 degrees, sin(x)+cos(x) equals square root of two. Which is not equal to one, and therefore you have a contradiction! That means that sin(x)+cos(x)=1 can't be an identity.
Oh, I see! So you basically have to plug in and prove that it isn't an identity
Yes. Because if it were an identity, it would be true for every value of x you give. But you can find an infinite number of values where that isn't true.
Makes sense. Thank you soo much.
You're welcome. ;D
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