Question

find m(x) if m(0) = 8 and
m'(x) = x^2 * e^(x^3)

Answer 1

a u sub should get it
put \(u=x^3, du=3x^2dx\) and you are almost done

Answer 2

@satellite73 help me with my question next please?

Answer 3

you get
\[\frac{1}{3}\int e^udu = \frac{1}{3}e^u+C=\frac{1}{3}e^{x^3}+C\] then solve for \(C\) since
\[m(0)=\frac{1}{3}+C=8\]

Answer 4

@brittneyy18rm i'll look at it

Answer 5

Thanks a bunch!