Question

Find the vertices and foci of the hyperbola with equation

Answer 1

\[\frac{ (x-3)^2 }{ 16} - \frac{ (y+4)^2 }{ 9 } =1\]

Answer 2

Center is (3,-4)
a^2=16, b^2=9
a^2+b^2=c^2
Vertices are a units to the right and a units to the left of the center.
Focal points are c units to the right and c units to the left of the center.

Answer 3

ok?