what is the solution of the following system -3x-2y=-12, 9x+6y=-9 a. (2,1) b. no solutions c.(-2,-1) d. infinitely many solutions
substitute
wait r u the one i helped 3 minutes ago? lol
haha yea lol
cool same thing here, try it yourself first
9x+6y=-9= -1
remember the whole point of substituting is to make an equation with only 1 variable, which we can easily solve. we cannot solve a function with more than 1 variable
so first, choose a function, then isolate a variable, x or y, then put it in terms of the other variable, then substitute it into the other equation.
if u choose to isolate x, u shud have an equation like x = something, u then have to put it in terms of y, meaning the "something" has only y in it, nothing else
so say u choose -3x-2y=-12 to isolate x (or y if u want), u get x = 4 - 2/3 y, following the format i mentioned above "x = something, u then have to put it in terms of y, meaning the "something" has only y in it,"
then plug x = 4 - 2/3 y into the second equation, then solve for y because now x is eliminated (substituted by y).
11calcBC...do you think this problem would be more easily solved with elimination. Because if you use substitution, you will be dealing with fractions.
yes that would be easier actually, im just trying to make clear to her the concept of substitution lol
I understand..and you are doing a good job...thumbs up :)
lol thanks mate!
9x4+6x-2/3??
show me ur equation first
36+4???
u know how to use elimintation?
what is that lol?
thats when make u directly add or subtract functions to eliminate a variable
that would leave only 1 variable behind, which is what we always want
whats the answer
b. no solutions
u sure
If you use elimination\[-3x -2y = -12\]\[9x + 6y = -9\]Multiply top by 3 that gives you\[-9x - 6y = -36\]However if you add the top and bottom equations than the variables will cancel out. You will end up with: \[nothing = -45\]Therefore you have no solutions.
thanks
No problem.
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