Question

Hi all! Need to check my work here "f(x): (2x-3)^4 (x^2 +x+1)^5"

Answer 1

f(x) = (2x - 3)^4 (x^2 + x + 1)^5

use product and chain rules

f'(x) = 4(2x-3)^3*2(x^2+x+1)^5 + (2x-3)^4*5(x^2+x+1)^4*(2x+1)

factoring, f'(x) =(2x^3)^3(x^2+z+1)^4[8(x^2+x+1)(2x+1)] that's it its ugly, but it's correct.

Simplifying is tedious and straight-froward, that's when I use a derivative calculator

Answer 2

let me check me answer hmm

Answer 3

(4(2x-3)^3 (2))(5(x^2 +x+1)^4 (2x+1))

Answer 4

does this work?

Answer 5

I tried using that method you showed me last time