Question

i seem to be getting this wrong and can't find out why. can someone help me and see where i went wrong?

Answer 1

\[\frac{ 12^n }{ (n+1)(8^(2n+1) }\]

Answer 2

use ration test to determine convergance

\[a_(n+1)= 12^(n+1)/((n+2)(8^2n+2))\]

\[\lim_{n \rightarrow \inf}\left| \frac{ 12^(n+1) }{ (n+2)(8^(2n+2) }*\frac{ (n+1)(8^(2x+1) }{ 12^n } \right|\]

\[\lim_{n \rightarrow \inf}\frac{ 12(n+1) }{ 8(n+2) }\]

=12/8

Answer 3

so it should be divergent. but webwork says its the wrong answer. did i mess up somewhere and i can't see it?

Answer 4

\(\large a_n = 8^{2n+1}\)

becomes

\(\large a_{n+1} = 8^{2n+3}\)

Answer 5

once u correct that, it ends in 12/64 in think

Answer 6

oh! thank you. i see it now. thank you very much!!

Answer 7

you're wlcme :)