If the diagonal length of a square is tripled, how much is the increase in the perimeter of that square?
if only the diagonal is tripled?
... i thought i read triangle lol
all linear aspects of a shape dilate the same
let the perimeter be defined as s+s+s+s, with a diagonal of d if the diagonal is scaled by some constant k, then all linear aspects adjust by the same factor giving us a perimeter of ks+ks+ks+ks = k(s+s+s+s)
how are we going to solve this problem?
i already explained how to solve it ....
let the perimeter be defined as s+s+s+s, with a diagonal of d if the diagonal is scaled by some constant k (what constant value did they use?), then all linear aspects adjust by the same factor giving us a perimeter of ks+ks+ks+ks = k(s+s+s+s) ^^ since it increase by k, what value of k did they use?
they haven't give the value of k
they have .. you need to reread and focus on how they manipulated the diagonal. They say that it is adjusted in a specific way ....
If the diagonal length of a square is tripled ------ ^^^^^^
k = 3x ?
yes :)
if they modify the diagonal by a factor of 3, then the perimeter is also modified by a factor of 3: |dw:1383137869978:dw|
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