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\frac{ 1 }{ 3 }*X*A+I _{2}=A ^{T} How do I proceed with this?
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Are those matrices? are you solving for X?
Yup
\[\frac{ 1 }{ 3 }*X*A+I _{2}=A ^{T}\]
what is A?
\[\left[\begin{matrix}3 & 6\\ 1& 3\end{matrix}\right]\]
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Would it be right to write it like this: \[X=(3A ^{T}-3I _{2})A ^{-1}\]
yeah
and then like this: \[X=3A ^{T}A ^{-1}-3I _{2}A ^{-1}\]
yeah, i think so, you know A so you can work out the right hand side,
Yup, I'll give it a try ;) Thanks!
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WOHOOO! Got the right answer!^^
good on ya!
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