Question

Write an equation of a line in slope intercept form that is perpendicular to y= -4x-2 passes through (-16,-11) .

Answer 1

If we want 2 line they are perpendicular they slope are this :
m2 = -1/m1
For example :
Find an equation perpendicular to y = 2x +8
We just find that slope line :
That slope is -1/2
So we have :
y=-1/2+8
Just this .
Got it ?

Answer 2

Can you explain a little bit more please?

Answer 3

And if we want that line through a point help from this :
Y-y2=m(X2-x)
x2 and y2 are the numbers we have in the Coordinate s line .
And x and y are in the form .
So in the example if we want that line through (-5 , 4) have :
y=-1/2+8 is our equation use from : Y-y2=m(X2-x) have :
y-4=-1/2(x-(-5))=>y-4=-1/2(x+5) and write it in standard form it s y=mx+d means :
y=-1/2x-5/2-4
y=-1/2-13/2

Answer 4

Of course !
Look at this example .
If we want a line perpendicular to another line :

(line d )

Answer 5

have :

Answer 6

that equation certainly have a slope that slope is Symmetric inverse .
Means if the slope for d is 2 for the black one is -1/2 .
Got it ?

Answer 7

yeah thanks

Answer 8

And we want the black line for example passes through (2 , 1) use this :
y2-y=m(x2-x)
y2=1
x2=2
m=-1/2
1-y=-1/2(2-x) ( I think had a fall in the first example there )
1-y=-1+1/2x
-y=-1-1+1/2x
y=+2-1/2x
And this is our end equation .

Answer 9

For your question you should find slope(m) first and use from :
y2-y=m(x2-x)
X2=-16
Y2=-11

Answer 10

@E.ali you have you equation wrong it y-y1=m(x-x1)
y-(-16)=1/4(x-(-11))
Distribute
y+16=1/4x+2.75
Subtract 16
y=1/4x-13.25