Algebra I Help? Parallel and Perpendicular Lines?
Hold on a sec.
The equation of a line is shown below.\[y=-\frac{ 1 }{ 3 }x-24\]What is the equation of a line which is perpendicular to this line and passes through (1, 27) a. y = 3x - 24 b. y = 7x - 24 c. y = 7x + 24 d. y = 3x + 24
bom dia kewlgeek ^_^ Parallel and perpendicular, it's all to do with slopes... that said, what's the slope of your given line?
Uh...3 over 1? ._.
You're not too sure of yourself...are you? :D
When you have the line given in THIS form: \[\Large y = \color{blue}mx +b\] the value \(\large \color{blue}m\) is the slope :)
T_T I didn't read the lesson! -crowd gasps-
Well I know THAT.
Don't worry, that's why I'm here, to DEAL with your behaviour >:)
Just kidding. and lol, if you did know that, then what's the slope of this line: \[\Large y = \color{blue}{-\frac13}x-24\]
The slope is 1 over 3 -duh.
Nope, it's -1/3 signs matter :)
OMGOMG IS IT:\[y=3x+24\]?????????????
Are you in any sort of hurry?
Well, can't lie to you, can I? Yes it is. How did you get it?
(I hate these multiple choice questions... they take away all the fun -_-)
Well I am so sorry for the late reply but my mom told me I had to go to lunch and it was such a short notice so I had to leave. Anyways I got it because I put everything opposite. the fraction got flipped and the subtraction sign got into a plus sign.
Still need help?
Well I do have one...
Sure thing...
Choose the equation of the line passing through the point (-1, 3) and perpendicular to:\[y=-\frac{ 1 }{ 3 }x+7\] a. y = 3x - 12 b. y = 3x + 6 c. y = 3x - 6 d. y = 3x
Well, since they all have the same slope the first part of the question is easy.
Because if a line has a slope = "m" Then a 2nd line perpendicular to that 1st line has a slope equal to -1/m
So it would be C?
Not quite...
Since you know the slope must be "3", just plug in the "-1" and "3" in point slope form.
i.e. y - 3 = 3(x - (-1)) and solve
Since, given a slope "m" and a point: \[(x_{0}, y_{0})\]
The equation of the line comes from the formula: \[y - y_{0} = m(x - x_{0})\] and then simplifying so that all the terms besides "y" are on the lefthand side.
0.0
So I solve y - 3 = 3(x - (-1))?
Exactly!
Okay. So I distribute first. The equation is now: y - 3 = 3x - 3
Wait.. look at the righthand side...
Because it's "-(-1)"
Sorry for the late reply. So it is -3?
Ok, so we have: \[y - 3 = 3(x - (-1))\]
What's another way to write: -(-1)?
+1??
Yeah!
So now rewrite that line I gave you y -3 = 3(x-(-1))
y - 3 = 3x + 3?
Yeah, now just add three to both sides.
y = 3x + 6
WOOHOO!
Yay! I have another one (sorry)
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