Question

k,

Answer 1

does your eq looks like this
\[\sqrt {x + 9} − 4=1\]

Answer 2

If yes then

Answer 3

\[\sqrt {x + 9} − 4=1 \rightarrow \sqrt {x + 9}=1+4 \rightarrow \sqrt {x + 9}=5\]
squaring both sides
\[(\sqrt {x + 9})^2=(5)^2 \rightarrow x+9 =25 \rightarrow x= 25-9\]
i.e. x= 16 is the required answer.

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Answer 4

Extraneous Solution is a solution of the simplified form of an equation that does not satisfy the original equation.

Here 16 satisfies the original eq so 16 is not an extraneous solution

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Answer 5

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Answer 6

@mathhelpnow Are you there?

Answer 7

You plug what you found for "x" back into the original equation. Then solve it. If it equals the original outcome that it gave you. Then it is the solution of the variable of the equation.