how would you prepare 5000gramsof 0.5 molal sodium hydroxide solution

Question

cwrw238 · Answer

1 liter 0.5 molar sodium hydroxide contains  0.5 * 1 mole of the substance

anonymous · Answer

10ml 5.000 M NaOH solution + 90ml H2O.

Explanation:
5.000 divided by 0.5000 = 10.
So you want it 1/10 of the strength it is now.
Thus, stick 1/10 of the final volume with 9/10 of the final volume.
You now have gone from a 5 M solution to a 0.5 M solution.

anonymous · Answer

MV = MV
5M * V = 100ml * 0.5M
V = 100ml * 0.5M/5M = 10ml

zpupster · Answer

1)Determine grams of water in 1000 grams solution

In 0.5 molal there is .5 mole NaOH in 1000 grams solvent

0.5 mole NaOH X (40 grams / 1 mole) = 20 grams NaOH

2)Total grams solution = grams of NaOH + grams of solvent

1000 grams solution = 20 grams + grams solvent

grams of solvent = 1000 - 20 = 980 grams solvent per 1000 grams solution

5000 grams solution X 980 grams water / 1000 grams solution = 4900 grams water

grams NaOH = Total grams of solution - grams of solvent

grams NaOH = 5000 - 4900 = 100 grams NaOH