Question

Medal!

Answer 1

for what

Answer 2

2. A local snail population grows according to the function g(x) = 200(1.03)2x. Demonstrate the steps to convert g(x) into an equivalent function with only x as the exponent. Then explain to Iris how the key features of this local snail population compares to the key features of the invasive population.

Answer 3

See does this equation work?
G(x) = 200(1.03)^2x
1.03 x 1.03 = 1.06
200x1.06=212.18
G(x) = 212.18x

Answer 4

ya I aint good with algebra sarroy bro

Answer 5

sorry*

Answer 6

np man ty any ways...

Answer 7

@SolomonZelman @Hero @GodIsMySavior please help? just a easy medal?

Answer 8

@skullpatrol please help

Answer 9

i might know someone who can help

Answer 10

@OrionsBelt
can you help this person on this problem

Answer 11

thanks!

Answer 12

So this is your original equation ?
\[G(x) = 200(1.03)^{2x}\] and you want to convert the equation to something equivalent that only has "x" as the exponent as in this example equation:\[H(x) = whatever^x\] is that what you're trying to do here?

Answer 13

it said to solve for g(x) right so i made this equation to try and solve for it...is it correct?

Answer 14

I don't think that's correct. Your question is asking you to change the original equation into an equivalent equation having only "x" as the exponent. Exponents are the upper case numbers or variables attached to a constant or another variable.

Unless you meant to solve the equation for G(x) so that only "x" is the only "variable" in the equation then your above equation would work.

Answer 15

example of exponent use:
\[G(x) = 200^x\]

"x" here is the exponent on top of the '200' constant

Answer 16

Yea...

Answer 17

(x)=(200)x(1.03)x(2)x=(200)x(2.06)x=412x
would this be it?

Answer 18

http://openstudy.com/study#/updates/52615cc1e4b0c23cd54aaf9b

Answer 19

Is the question done?

Answer 20

No. I'm trying to solve your equation so it is equivalent to original and having only "x" as the exponent.

Answer 21

so we take out 1.03?

Answer 22

sorry im horrible at math....

Answer 23

In your original equation did it look Equation #1:
\[G(x)=200(1.03)^{2x}\]or did you mean as Equation #2:\[G(x)=200(1.03)^2x\]Please pick which equation was shown in your original problem

Answer 24

first one.

Answer 25

Alright. Since the exponents only applied to the "1.03" in the original equation, we can look at it as so:
\[G(x) = 200((1.03)^2)^x\]in which we can simplify the inner "1.03" which was squared:
\[G(x) = 200(1.0609)^x\]Now you have only "x" as the exponent of the equation and it is equivalent to your original equation. One way to check this is to plug in numbers such as "2" "3" "4" in for "x" and see if both equations give the same output. In which they do!

Answer 26

and im not right right so if i take 2 and plug it is it will look like g(2) = 200(1.06)^2

Answer 27

Yes. Remember it's 1.0609 not just 1.06 always take accuracy into consideration. See if both equations give you the same output. If it does, then they are equivalent.

Answer 28

So my answer would be g(2) = 200(1.0609)^2?

Answer 29

No. Your question asked you to write another equation that would be equivalent for the first. You are not solving for "x"

Answer 30

so it would be g(x) = 200(1.0609)^x?

Answer 31

Yes. Read your question again and think why that is the answer. If you're confused on any words in the question, the best thing to do is to google it's definition and see what I did to make the equation right.

Answer 32

so really i went 2 far into the equation? i should have stopped at 1.03 x 1.03?

Answer 33

Exactly. You have to pay attention to where the "exponents" are attached to. In certain situations, you can't combine them or multiply the numbers together.

In this equation the exponents are attached to the "1.03" only, so we could only apply them to that part of the equation. The "200" had none, so we left that alone and simplified the other.

Answer 34

ok i have somemore questions following up on this so ill close and make a new one.

Answer 35

Okay.

Answer 36

I had that question and I asked multiple high school math teachers and only one could figure it out (a calculus teacher) and she told me it was (206)^x * (206)^x. Because 200 * 1.03 = 206 and when you multiply numbers with the same exponents you add the exponents. So it is (206)^x * (206)^x.

Answer 37

Did you get all of these answers from this assignment ?