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Mathematics 7 Online
OpenStudy (anonymous):

how to derive (x^2-2x)^(1/2)

OpenStudy (raden):

use the chain's rule

OpenStudy (raden):

derivative of y = sqrt(f(x)) is y' = (f(x))'/(2sqrt(f(x)))

OpenStudy (anonymous):

so the numerator of that equation is f(x) prime?

OpenStudy (raden):

(f(x)) ' = f ' = derivative of f(x)

OpenStudy (anonymous):

Im guessing you ignore the radical for using that formula right? so you would get (2x-2)/2sqrt(x2-2x) ?

OpenStudy (raden):

yes, that's right. then simplify again

OpenStudy (anonymous):

simplifying to (x-2)/(sqrt(x^2-2x))?

OpenStudy (raden):

correct again, or you can do rationalize it

OpenStudy (anonymous):

thank you!

OpenStudy (raden):

you're welcome

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