fully factor? (2x+1)^2 - (3x-2)^2

Question

jdoe0001 · Answer

$\bf (2x+1)^2 - (3x-2)^2\implies (2x+1)(2x+1) - (3x-2)(3x-2)$

anonymous · Answer

i got there, and then i got this:
2x^2+4x+1-9x^2-12x+4

anonymous · Answer

which simplifies to: -7x^2-8x+5, but it doesn't factor nicely from there...?

jdoe0001 · Answer

ohhh shoot.. you said factor... I see

jdoe0001 · Answer

my bad... one sec... recall that $\bf \large a^2-b^2 = (a-b)(a+b)$

jdoe0001 · Answer

what you were doing was simplifying, but thtey  just want it factored

anonymous · Answer

yeah i put it into standard form so i could factor it but it doesn't factor nicely?

jdoe0001 · Answer

firstly     $\bf (2x+1)^2 - (3x-2)^2\implies [4x^2+4x+1]-[9x^2-12x+4]\ \quad \
4x^2+4x+1-9x^2+12x-4\implies -5x^2+16x-3$

jdoe0001 · Answer

secondly, I gather that once you get the "standard form", then you'd factor it, you'd end up with a form like $\bf a^2-b^2 = (a-b)(a+b)$  anyway

anonymous · Answer

oops i guess i should know how to add if i'm doing math... i got it now thanks!