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Eliminate the parameter. x = radical t , y = 2t + 5
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I just started learning this, so you have\[x=\sqrt{t}\]and\[y=2t+5\]So you can get t by itself in x=sqrt t\[x=\sqrt{t}=>x ^{2}=t\]Plug t into y=2t+5\[y=2(x ^{2})+5\]
so you just get t by itself and plug it in?
I think so, and when graphed, you have to make sure only graph where t exists.
Thank you! That was pretty easy haha also lets say i have an x=7t, for my next question, would the x be x=x/7?
Did it just give you x=7t?
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No other equation?
no x=7t, y=t+4 but i think the answer is y= x/7 +4 is that right?
Yeah
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