Question

how to find the third degree coefficients of -3 and sqaure root 5

Answer 1

oops I meant \[\sqrt{2}\]

Answer 2

can you add more info... I don't understand the question

Answer 3

That's all the question says.

Answer 4

what are you studying ?

Answer 5

well it says... Write the simplest third degree polynomial function of -3 and \[\sqrt{2}\]& Algebra 2 Trig

Answer 6

that sounds different from "how to find the third degree coefficients of -3 and sqr(2)"

but it is still not clear. If it said
" Write the simplest third degree polynomial function whose roots are -3 and
sqr(2)"

we could do that.

Answer 7

sorry I don't remember exactly,but if you could tell me hoe to do " Write the simplest third degree polynomial function whose roots are -3 and
sqr(2)" kind of problems that's be great too.

Answer 8

use roots x=-3, x= -\(\sqrt{2}\) and x =\(\sqrt{2}\)
x= -3
add +3 to both sides
x+3 = 0

x= -\(\sqrt{2}\)
add \(\sqrt{2}\) to both sides
x+\(\sqrt{2}\) =0

x= \(\sqrt{2}\)
add -\(\sqrt{2}\) to both sides
x-\(\sqrt{2}\) =0

now multiply all there together
(x+3)(x+\(\sqrt{2}\) )(x-\(\sqrt{2}\) )=0

can you multiply that out ?

Answer 9

I think I can... Thanks!

Answer 10

@phi I would use the box method, correct?

Answer 11

what is the box method ?

if you are asking how to multiply out the factors, first
do (x + sqr(2))(x- sqr(2)) to get x^2 - 2
now do
(x+3)(x^2 - 2)
one way is "distribute". in other words, this is the same as A( x^2 - 2)= Ax^2 + A(-2)
where A is (x+3)

Answer 12

Or see
http://www.khanacademy.org/math/algebra/multiplying-factoring-expression/multiplying-binomials/v/multiplying-polynomials1

Answer 13

sorry, I didn't know you replied. I didn't get a notification,but the box method is when you multiply all the binomials together basically using a box...