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Computer Science 14 Online
OpenStudy (christos):

Electrical Engineering , Can you please help me with this? https://www.dropbox.com/s/jrrk8qv9p359um6/Screenshot%202013-10-31%2000.27.33.jpg I am totally new to EE !

OpenStudy (christos):

@agent0smith

OpenStudy (christos):

@dan815

OpenStudy (christos):

@e.mccormick

OpenStudy (christos):

@Emily778

OpenStudy (christos):

@Hero

OpenStudy (christos):

@LoveYou*69

OpenStudy (christos):

And if you want to know the answers: https://www.dropbox.com/s/n0ag4mnhji1mo54/Screenshot%202013-10-31%2001.17.55.jpg I Know the answers I just want the method

OpenStudy (e.mccormick):

Know your parallel and series rules?

OpenStudy (christos):

Partly dude :S Today is my very first day on EE

OpenStudy (christos):

if a resistor is in the middle you divide

OpenStudy (christos):

if there is e1 up and e2 does you say e1 - e2 / R

OpenStudy (christos):

or something

OpenStudy (christos):

down*

OpenStudy (e.mccormick):

For simple circuits, you can use the basic rules: http://physics.bu.edu/py106/notes/Circuits.html

OpenStudy (e.mccormick):

The voltage at any point is related to the resistance.... Hmm... for more complex solutions I have gone over a way to do it using linear algebra, but did not practice that a ton.

OpenStudy (christos):

I can use the LMD

OpenStudy (e.mccormick):

Looking at this, it seems to explain the right formulas for doing this: http://www.facstaff.bucknell.edu/mastascu/elessonshtml/Resist/Resist2.html I went software rather than hardware, so my engineering knowledge is limited. =/ In fact, what I know has to do with what I had to learn for radio-electronics. LOL

OpenStudy (christos):

haha I see, np dude its ok : P

OpenStudy (agent0smith):

I can kinda do this but wouldn't be able to explain it too well as it's been a few months since i last tutored someone in this, but you have to use kirchoff's voltage laws, add up the voltages around each loop.

OpenStudy (christos):

I know its something with this law but I don't know what and why :p

OpenStudy (agent0smith):

You have to treat each "loop" separately, and add up the voltages around each loop. Take into account direction. eg bottom right loop: |dw:1383176021590:dw| KVL says that the sum of voltages around a loop is zero v3 + v5 - v2 = 0

OpenStudy (christos):

so I can find v5 from this equation you just did ?

OpenStudy (agent0smith):

Yes. And do the same thing for all other loops

OpenStudy (christos):

oh wait I don't have the value of v2 as well

OpenStudy (agent0smith):

Keep solving loops and substituting when you find something you know

OpenStudy (christos):

can you tell me what other loops can you see ?

OpenStudy (agent0smith):

|dw:1383176424570:dw| 4 would be the whole loop, i think KVL still applies to it too...

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