Question

What is the solution of log((2x + 7))27 = 3?

Answer 1

Is that (2x+7) raised to 27? (Is 27 an exponent?)

Answer 2

uhm the 2x+7 is like an exponent but lower not higher

Answer 3

Does it look like this?\[\Large \log_{(2x+7)} 27 = 3\]

Answer 4

yes

Answer 5

\[\Large \log_{b} A = C\]means\[\Large A = b^{C} \]Can you take it from here?

Answer 6

soo 27=2x+7^3?

Answer 7

Exactly. But you need to put parenthesis: 27=(2x+7)^3
Take the cube root on both sides.

Answer 8

19683=2x+343
I got 9,670

Answer 9

wait so just cube the 2x and 7?

Answer 10

27=8x+343
-316
with that i got -39.5

Answer 11

No. Cube root of 27 is 3 because 27 = 3 x 3 x 3

Cube root of (2x+7)^3 is: [ (2x+7)^3 ]^1/3. The 3 and 1/3 will cancel out leaving you with just (2x+7)

So 2x + 7 = 3. Solve for x

Answer 12

-2

Answer 13

thank you that's one of the answers!

Answer 14

Yes. That is the correct answer.
You are welcome.