Question

4x^2 < 9

help please c:

Answer 1

its a quadratic inequality btw. :o

Answer 2

Divide both sides by 4. Take the square root on both sides.
Note: a square root has both negative and positive roots. So solve both cases.

Answer 3

\[4x^2-9<0\]
\[(2x+3)(2x-3)<0\] zeros are at \(-\frac{3}{2}\) and \(\frac{3}{2}\) and since
\[y=4x^2-9\]is a parabola that opens up, it is negative between the zeros

Answer 4

and of course
\[4x^2-9<0\] is the same as solving "for which \(x\) is \(4x^2-9\) negative"