Anyone? Landon opened a savings account with a deposit of $3,786.45. Nine years later, the balance in the account is $5,135.29. If the interest rate is 3.4%, how often does the interest compound? daily monthly quarterly annually
Hint: use the formula A = P(1+r/n)^(n*t)
In this case P = 3786.45 r = 0.034 t = 9
Plug these values into the formula A = P(1+r/n)^(n*t) to get A = P(1+r/n)^(n*t) A = 3786.45(1+0.034/n)^(n*9)
The goal is to find the value of n which makes A equal to 5135.29
Common of values of n are n = 1 (annual compounding) n = 2 (semi-annual compounding) n = 4 (quarterly compounding) n = 12 (monthly compounding) n = 365 (daily compounding)
So plug in each value of n listed above into A = 3786.45(1+0.034/n)^(n*9) ------------------------------------------------------- So for instance, if n = 1, then A = 3786.45(1+0.034/n)^(n*9) A = 3786.45(1+0.034/1)^(1*9) A = 5115.84143581059 A = 5115.84 which is NOT the value of 5135.29, so we must move onto other values of n and check them
This rules out annual compounding as a possible answer choice
does all this make sense?
yes,its not C or D. I'm stuck between choosing A or B :/
You can use my formula and change the n into the corresponding number and take a look at the answer if its the same as the given which is $5,135.29
also, I answered your other question
monthly right?
Yep :D
yayyy and whats the answer to the taylor one? its my last one, please just fill me in lol
? @GirlByte
pleeasse
I'm back lol. Just follow the solution
I've been doing questions all night, this is my last one could you do me this one tiny favor?
Sure
its 58
thank you so much, have a nice evening :)
yw :)
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