Question

solve the following equation. sin^2 x + sin x=0

Answer 1

Since sin²(x) really equals (sin(x))², we can replace sin(x) with some other variable, a.
(Later we'll come back and solve for x)

sin²(x) + sin(x) = 0
sin(x) = a

so:
a² + a = 0

Can you solve that for a?

Answer 2

thats what i did, which i think took "a" out which left me with a(a+1)

Answer 3

then i solved sin x =0 and sin x =-1

Answer 4

which would then be pi and 3pi/2

Answer 5

would it be +2npi or would it just be +npi?

Answer 6

You have the right values for sin(x), but I think your values for x are a bit off.

Answer 7

what do mean?

Answer 8

Wait, they're right. But the simplest value for asin(0) = 0
So you would have:
0+n(pi)
(3pi/2)+2n(pi)

Answer 9

sinx = 0 so then that would mean sin = pi on the chart we made in class?

Answer 10

sin(x) is the y value of the unit circle. There are 2 points where this y value is 0:

Answer 11

your x value is x=1