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A body is moving upward with a vel0city of 500ms^-1 what will be the height?
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@AllTehMaffs
use the relation v = u -gt and v = 0 so calculate t and then use the relation S = ut -.5gt^2
u = 500m/s v = 0m/s a = -9.81 m/s^2 You can use dibuaman's method, or forget about time and use the 4th equation of motion \[\cancel{v^2}^0 = u^2 + 2ah\] \[h = -\frac{u^2}{2a}\] |dw:1383200487207:dw|
ty MASTER maff :)
hahaha, welcome ^_^
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\[1/2 mv ^{2}=mgh\]
by cancelling mass with each other we get\[1/2 v ^{2} = gh \]
then we get\[v ^{2}/2g=h\]
use the above equation to solve the problem
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