Question

Evaluate the limit.

Answer 1

\[\lim_{x \rightarrow \infty}\frac{ e ^{6x} }{ \sinh^2(3x) }\]

Answer 2

use:\[\sinh(x) = \frac{ e^x - e^{-x} }{ 2 }\] and realize that\[\sin^2h(x) = (\sinh(x))^2\]

so expand the denominator, it will have terms of e^[6x}