Question

solve cos^2 x-5sin x +5=0

Answer 1

step by step please

Answer 2

convert cos^2 x into sin^2 x then take sin x =t solve the quad then substitue t =sin x AND get ur soln
AM NOT GIVING OUT THE WHOLE SOLUTION

Answer 3

\[1-\sin ^{2}x - 5 \sin x + 5\]

Answer 4

u r going r8

Answer 5

then, \[-\sin ^2 x -5 sinx +6\]

Answer 6

then, \[-(sinx - 1)(\sin x+6)\]

Answer 7

then you solve sin x =-1 and sin x=6 right?

Answer 8

which would be 2pi and pi?

Answer 9

right and sinx cant be 6 implies sinx to be 1

Answer 10

im lost there

Answer 11

why does it do that?

Answer 12

coz sin graph is confined between -1 and 1

Answer 13

okay, so if it is 6 i thought it was undefined...

Answer 14

yess u did that good

Answer 15

so then why would sin x =6 be 1?

Answer 16

sin x could be 1 or 6......
we cant choose 6 as it solution coz sin has range of [-1,1] so the only soln left is sin x=1

Answer 17

now u get it?

Answer 18

so it would be Pi/2 +2npi

Answer 19

but at the beginning of it you have -(sin x-1)(sin x +6) what do u do with the negative in the front?

Answer 20

general soln is diff from this

Answer 21

because sin x can't equal 6 so that would be thrown out

Answer 22

idk what you mean

Answer 23

no prob of negative sign coz of zero on other side

Answer 24

ok

Answer 25

when we write soln in term of n... then its called the general soln and that is diff from urs

Answer 26

so??? it would be what? just +npi? or just pi/2

Answer 27

x = nπ + (-1)ⁿ.pi/2

Answer 28

why would it be a negative pi/2

Answer 29

i dont get that

Answer 30

what you are saying

Answer 31

it looks to me what you just sent me it is -1pi/2

Answer 32

or is it just pi/2+npi

Answer 33

its n (pi) + (-1)^n pi/2

Answer 34

and n is a whole no.

Answer 35

okay

Answer 36

so yes or no your answer is pi/2+npi

Answer 37

ques clear?

Answer 38

my answer is already stated above

Answer 39

so what do u say?